Variance(s2^22) = ∑(x−x‾)2n\; \frac{\sum (x - \overline{x})^2}{n}n∑(x−x)2
But mean = 50 (from question 39 same information)
x
x - x‾\overline{x}x
(x - x‾)2\overline{x})^2x)2
∑(x−x‾)2\sum (x - \overline{x})^2∑(x−x)2 = 280
Variance(s2^22) = ∑(x−x‾)2n\; \frac{\sum (x - \overline{x})^2}{n}n∑(x−x)2 = 2808\; \frac{280}{8}8280 = 35
