For what values of y is \;y + 2/8y² - 10y + 3 not defined?

Correct Answer is : 34\;3/443, 12\;1/221

Correct Answer is : 34\;3/443, 12\;1/221

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WAEC Mathematics 2024 Paper

Question : 50

Total: 50

\;\frac{y + 2}{8y^2 - 10y + 3}

not defined?

Solution:

$\;\frac{y + 2}{8y^2 - 10y + 3}$ not defined when the denominator is equal to zero

8y $^2$ - 10y + 3 = 0 using factorization method

8y $^2$ - 6y - 4y + 3 = 0

2y(4y - 3) - 1(4y - 3) = 0

(4y - 3)(2y - 1) = 0

4y - 3 = 0 or 2y - 1 = 0

Hence, y = $\;\frac{3}{4}$ or $\;\frac{1}{2}$

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