(3 - 42\sqrt{2}2)(1 + 32\sqrt{2}2) = a + b2\sqrt{2}2,
3 + 92−42−(42×32)=a+b2\sqrt{2} - 4\sqrt{2} - (4\sqrt{2} \times 3\sqrt{2}) = a + b\sqrt{2}2−42−(42×32)=a+b2
3 + 52−(4×32×2)=a+b2\sqrt{2} - (4 \times 3\sqrt{2} \times \sqrt{2}) = a + b\sqrt{2}2−(4×32×2)=a+b2
3 + 52−(12×2)=a+b2\sqrt{2} - (12 \times 2) = a + b\sqrt{2}2−(12×2)=a+b2
3 + 52−24=a+b2\sqrt{2} - 24 = a + b\sqrt{2}2−24=a+b2
-21 + 52\sqrt{2}2 = a + b2\sqrt{2}2
Comparing both sides, we have b = 5
