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WAEC Mathematics 2024 Paper

Question : 8

Total: 50

If log

_{3}^{2x - 1}

= 5, find the value of x

Solution:

log $_{3}^{2x - 1}$ = 5 in index form becomes 3 $^{5}$ = 2x - 1

2x - 1 = 243

2x = 243 + 1 = 244

x = $\; \frac{244}{2}$ = 122

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