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WAEC Mathematics 2025 Paper

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Question : 9

Total: 50

If

\frac{16}{9}

, x, 1, y are in geometric progression (G.P.). Find the product of x and y.

$\frac{16}{9}$
$\frac{3}{4}$
1
$\frac{4}{3}$

Solution:

Concept:

In a geometric progression (G.P.), the ratio between any two consecutive terms is constant.

Explanation:

Let the common ratio be

r

.

Using the equal ratios:

\frac{x}{\frac{16}{9}} = \frac{1}{x}

.

So,

x^2 = \frac{16}{9}

.

Thus,

x = \frac{4}{3}

.

Now,

r = \frac{1}{x} = \frac{3}{4}

.

Then,

y = 1 \times \frac{3}{4} = \frac{3}{4}

.

Therefore, product of

x

and

y

is

\frac{4}{3} \times \frac{3}{4} = 1

.

Answer:

1

Correct option: C.

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