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WAEC Physics 2010 Paper

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Question : 24

Total: 50

A certain wave has a speed of 20ms^-1. If the frequency of the wave is 0.25Hz, calculate the distance between successive crests of the wave

5.0m
40.0m
50.0m
80.0m

Solution:

Concept:

The distance between successive crests is the wavelength

\lambda

of the wave.

Explanation:

Use the wave relation

v = f\lambda

.

Rearrange to get

\lambda = \dfrac{v}{f}

.

Substitute

v = 20\ \mathrm{m\,s^{-1}}

and

f = 0.25\ \mathrm{Hz}

.

\lambda = \frac{20}{0.25} = 80\ \mathrm{m}

Thus, the distance between successive crests is

80.0\ \mathrm{m}

.

Answer:

80.0\ \mathrm{m}

(Option D).

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