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WAEC Physics 2010 Paper

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Question : 28

Total: 50

From the diagram, the correct equation for the refractive index n of the medium is

n = tan i
n = $\frac{\sin i}{\sin 90^{\circ}}$
n = $\frac{\sin i}{\cos(90^{\circ} - i)}$
n = sin 90^oC

Solution:

refractive index(n) = $\frac{\sin i}{\sin r}$

where r = 180-(90+i) → r=90-i

since sin(90-i)=cos i

: refractive index(n) = $\frac{\sin i}{\cos i}$

→ tan i

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