6Ω and 4Ω are parallel.
1RT\frac{1}{R_T}RT1 = 1R1+1R2\frac{1}{R_1} + \frac{1}{R_2}R11+R21
1RT\frac{1}{R_T}RT1 = 16+14\frac{1}{6} + \frac{1}{4}61+41
RTR_TRT = 125\frac{12}{5}512 = 0.97Ω
V = IR
