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WAEC Physics 2012 Paper

Question : 10

Total: 47

Solution:

Concept:

Use the equation of motion for a freely falling object starting from rest:

H = \frac{1}{2}gt^2

Explanation:

The object is dropped, so its initial velocity is

u = 0

The acceleration due to gravity is

g = 10 \, \text{ms}^{-2}

Time taken is

t = 4 \, \text{s}

Using

H = ut + \frac{1}{2}gt^2

, and since

u = 0

H = \frac{1}{2} \times 10 \times (4)^2

H = \frac{1}{2} \times 10 \times 16 = 80 \, \text{m}

Therefore, the height of the tower is

80 \, \text{m}

Answer:

C. 80 m

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