Test Index

WAEC Physics 2012 Paper

Question : 21

Total: 47

^{-1}

^{-1}

^{-1}

]

Solution:

Mice = $\; \frac{MC}{\theta}$

= \(\frac{20 \times 0.4 \times 110}{330}

Heat lost by copper = Heat gained by ice

m $_{\text{copper}}$ c $\theta$ = m $_{\text{ice}}$ L

20 x 0.4 x (110 - 0) = m $_{\text{ice}}$ x 330

m $_{\text{ice}}$ = $\; \frac{20\; \times\; 0.4\; \times\; 110}{330}$

= $\; \frac{8}{3}$

= 2.67 g

= 2.70g (to 1 d.p)

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