Africa Exams
Where Preparation Meets Success
Home
Botswana
Botswana PSLE Papers
Botswana JCE Papers
Botswana BGCSE Papers
Ghana
Ghana BECE Exams
Kenya
Kenya KCPE Papers
Kenya KCSE Papers
Kenya KASNEB Papers
Nigeria
WAEC Exams
JAMB Exams
Rwanda
Rwanda Primary Papers
Rwanda Secondary Papers
Uganda
Uganda PLE Papers
Uganda UCE Papers
Uganda UACE Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
WAEC Physics 2013 Paper
Show Para
Hide Para
Share question:
© africaexams.com
Question : 32
Total: 46
A potential difference of 12V is applied across the ends of a 6
Ω
resistor for 10 minutes. Determine the quantity of heat generated
720J
1200J
14400J
43200J
Validate
Solution:
Q = \(\frac{V^2 t}{R}
= \frac{12^2 \times 10 \times 60}{6}\)
= 14400J
© africaexams.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
Prev Question
Next Question
