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WAEC Physics 2013 Paper

Question : 6

Total: 46

^{-2}

]

Solution:

Concept:

For a body sliding freely down a smooth inclined plane, its acceleration is the component of gravitational acceleration along the plane.

Explanation:

The acceleration down the plane is given by:

a = g \sin \theta

Here,

g = 10\, \text{ms}^{-2}

and

\theta = 60^\circ

So,

a = 10 \sin 60^\circ

Since

\sin 60^\circ = 0.8660

a = 10 \times 0.8660 = 8.66\, \text{ms}^{-2}

Rounded to one decimal place, this gives

8.7\, \text{ms}^{-2}

Answer:

The acceleration of the body down the plane is

8.7\, \text{ms}^{-2}

, which corresponds to option D.

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