Concept:An object suspended in a liquid appears lighter because of the upthrust, equal to the weight of the displaced liquid.Explanation:Mass of object =density×volume=2.5×400=1000 gVolume of water displaced =2400=200 cm3Loss in mass =volume displaced×density of water=200×1=200 gReading on spring balance =actual mass−loss in mass=1000−200=800 gAnswer:The reading on the spring balance is 800 g.Correct option: C. 800g