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WAEC Physics 2017 Paper

Question : 12

Total: 50

The angle at which a projectile must be fired to cover maximum range is

Solution:

The formula is $\frac{v^{2}\sin 2\theta}{g}$

And the sine graph is highest at 1 with its inverse as 90°. Hence, $2\theta$ = 90°

$\theta$ = 45°

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