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WAEC Physics 2017 Paper

Question : 26

Total: 50

Solution:

Concept:

For an open pipe, the

n

th harmonic has

n

nodes and

n+1

antinodes.

Explanation:

The fundamental is the 1st harmonic.

The 3rd overtone is the 4th harmonic.

So,

n = 4

Number of nodes

= n = 4

Number of antinodes

= n+1 = 5

Hence, the 3rd overtone of an open pipe has 4 nodes.

Answer:

The correct option is A: 4 nodes.

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