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WAEC Physics 2017 Paper
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© africaexams.com
Question : 30
Total: 50
The diagram above illustrates a wave setup between two fixed ends 4.0m apart. If the speed of the wave is 1.0
m
s
−
1
, its wavelength and frequency respectively are
1m; 0.25Hz
2m; 0.25Hz
2m; 0.50Hz
4m; 0.50Hz
Validate
Solution:
For the 4th harmonic,
L
=
2
λ
4
m
=
2
λ
implies
λ
=
4
m
2
=
2
m
Recall,
v
=
f
λ
1
=
f
×
2
implies
f
=
1
2
= 0.50Hz
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