The resistors are connected both in parallel and series. To calculate the total resistance, we have:
For the parallel connection: 1R=11+11\frac{1}{R} = \frac{1}{1} + \frac{1}{1}R1=11+11
1R=2⇒R=0.5Ω\frac{1}{R} = 2 \Rightarrow R = 0.5\OmegaR1=2⇒R=0.5Ω
For the series connection: Rtotal=(1+0.5)Ω=1.5ΩR_{total} = (1+0.5)\Omega = 1.5\OmegaRtotal=(1+0.5)Ω=1.5Ω
Recall, V=IRV = IRV=IR
3=1.5I⇒I=31.5=2A3 = 1.5I \Rightarrow I = \frac{3}{1.5} = 2\mathrm{A}3=1.5I⇒I=1.53=2A