Test Index

WAEC Physics 2017 Paper

Question : 40

Total: 50

V_{r.m.s}

Solution:

$N_{p} = 3000 \text{ turns}$

$N_{s} = 500 \text{ turns}$

$E_{p} = 240 V_{r.m.s}$

$E_{s} = ?$

$\frac{N_{s}}{N_{p}} = \frac{E_{s}}{E_{p}}$

$\frac{500}{3000} = \frac{E_{s}}{240}$

$\implies E_{s} = \frac{240 \times 500}{3000} = 40V$

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