Let the room temperature be X.
We have, 3−010−0= X−0100−0\; \frac{3-0}{10-0} = \; \frac{X-0}{100-0}10−03−0=100−0X−0
310= X100\; \frac{3}{10} = \; \frac{X}{100}103=100X
X= 3×10010X = \; \frac{3 \times 100}{10}X=103×100
= 30°C