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WAEC Physics 2018 Paper

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Question : 35

Total: 50

A wire of length 400cm is stretched between two fixed points. When plucked, its fundamental frequency is 150Hz. Calculate the speed of the wave produced.

250 $\mathrm{ms}^{-1}$
625 $\mathrm{ms}^{-1}$
1200 $\mathrm{ms}^{-1}$
1500 $\mathrm{ms}^{-1}$

Solution:

The fundamental frequency $(f_{0})$ = $\;\frac{v}{2l}$

$f_{0} = 150\,\mathrm{Hz};\; l = 400\,\mathrm{cm} = 4\,\mathrm{m}$

$150 = \;\frac{v}{2 \times 4}$

$v = 150 \times 8 = 1200\,\mathrm{ms}^{-1}$

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