Heat needed to change 60g (0.06kg) of ice at 0oC to water at 0o
= 0.06 x 3.36 x 105J
= 0.2016 x 105 J
Heat required to raise the temp. of 60g (0.06kg) of water from 0oC to 80oC
= 0.06 x 4.2 x 103 x (80.0)J
= 0.06 x 4.2 x 103 x 80
= 20.16 x 103
= 0.2016 x 105
Total heat needed = (0.2016 + 0.2016) 105J
= 0.4032 x 105 J
= 40.32KJ
