Given that refractive index = 1.5, angle of incidence = 30°, angle of refraction =?
using snell's law = refractive index = sinisinr\frac{\sin i}{\sin r}sinrsini
=1n=sin30sinr\frac{1}{n} = \frac{\sin 30}{\sin r}n1=sinrsin30
= sinr=1.5×sin30\sin r = 1.5 \times \sin 30sinr=1.5×sin30
r = sin−10.75\sin^{-1} 0.75sin−10.75
= 48.6°
this is because ray is traveling from a more denser medium to a less dense medium
