GIVEN DATA:where ΔL is the increase in length =0.01L 1 is the initial length =100T1=20T2=?a is the linear expansivity of iron =1.2×10−5∘C FormulaΔL=L1aΔTΔT=L1αΔLΔT is the change in temperature =T2−T1T2=L1αΔL+T1T2=100×1.2×10−50.01+20T2=8.3+20T2=28.3