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WAEC Physics 2021 Paper

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Question : 36

Total: 50

A force of 10 N, acting continuously, increases the kinetic energy of an object from 20.J to 60 J. Find the distance moved by the object.

200m
40m
4m
400m

Solution:

according to the work-energy theorem; Workdone = change in kinetic energy.

W = ∆ K.E

force x distance = $K.E_2 - K.E_2$

10 x s = 60 - 20

s = $\; \frac{40}{10}$ = 4m.

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