Concept:In an open tube, the first overtone corresponds to one complete wavelength inside the tube.
Explanation:For an open tube, both ends are free to vibrate, so both ends are antinodes.
For the fundamental mode, the length is
l=2λ.
For the first overtone, the wavelength decreases so that
l=λ.
Therefore, the correct diagram must show a full wavelength in the tube.
This full-wave pattern has antinodes at both ends and at the middle, with nodes at the
41 and
43 positions.
So, the diagram showing
l=λ in an open pipe is the correct one.
Answer:Choose the diagram that shows the open tube containing one full wavelength, i.e.,
l=λ.