A particle of mass 3.6 x 10^{-6}kg revolving around the earth has a radial acceleration of 4.3 x 10^7ms^{-2}. Calculate the centripetal force of the particle.

Correct Answer is : 1.55 x 102²2N

Correct Answer is : 1.55 x 102²2N

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WAEC Physics 2024 Paper

Question : 20

Total: 50

^{-6}

^7

^{-2}

. Calculate the centripetal force of the particle.

Solution:

Concept:

Centripetal force is the product of mass and radial (centripetal) acceleration.

Explanation:

Given mass,

m = 3.6 \times 10^{-6}\,\text{kg}

Given radial acceleration,

a_r = 4.3 \times 10^{7}\,\text{ms}^{-2}

This radial acceleration is the centripetal acceleration,

a_c

Use the formula

F_c = m a_c

Substitute the values:

F_c = (3.6 \times 10^{-6})(4.3 \times 10^{7})

Multiplying:

3.6 \times 4.3 = 15.48

and

10^{-6} \times 10^{7} = 10^{1}

F_c = 154.8\,\text{N} \approx 155\,\text{N}

In standard form,

F_c = 1.55 \times 10^{2}\,\text{N}

Answer:

1.55 \times 10^{2}\,\text{N}

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