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WAEC Physics 2024 Paper

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Question : 27

Total: 50

The diagram above illustrates two boxes P and Q of masses 27.3 kg and 6.2 kg respectively on a smooth horizontal surface. If a force F of 150 N is applied to the combined forces, calculate the acceleration.

4.5 ms $^{-2}$
33.5 ms $^{-2}$
70 ms $^{-2}$
150 ms $^{-2}$

Solution:

Concept:

Use Newton's second law:

F = ma

.

Since the boxes move together, add their masses to find the total mass.

Explanation:

Total mass of the two boxes,

P

and

Q

, is:

m = 27.3 + 6.2 = 33.5\ \text{kg}

.

The applied force is

F = 150\ \text{N}

.

From

F = ma

, the acceleration is:

a = \frac{F}{m} = \frac{150}{33.5} = 4.4776\ \text{ms}^{-2}

.

Rounding to one decimal place gives:

a \approx 4.5\ \text{ms}^{-2}

.

Answer:

The acceleration is

4.5\ \text{ms}^{-2}

, which is option A.

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