Arrange 2/4,4/9, and 3/7 in ascending order.

Correct Answer is : 37⋅ 49 23\;\;3/7 · \;4/9 \;2/373⋅9432

Arrange 2/4,4/9, and 3/7 in ascending order.

Correct Answer is : 37⋅ 49 23\;\;3/7 · \;4/9 \;2/373⋅9432

Test Index

BECE Mathematics 2018 Paper

Question : 10

Total: 40

Arrange

\frac{2}{4},\frac{4}{9}

, and

\frac{3}{7}

in ascending order.

$\;\;\frac{2}{3} \;\frac{3}{7} \cdot \;\frac{4}{9}$
$\;\;\frac{4}{9} \;\frac{3}{7} \;\frac{2}{3}$
$\;\;\frac{3}{7} \;\frac{2}{3} \;\frac{4}{9}$
$\;\;\frac{3}{7} \cdot \;\frac{4}{9} \;\frac{2}{3}$

Validate

Solution:

Make sure the denominators are the same for each fraction by multiplying both the numerator and denominators by the number of times the denominator goes into the L.C.M

The L.C.M of 3,9 and 7 is 63

Thus:

3\;=3

9\;=3 \times 3=3^{2}

7\;=7

To get the L.C.M, multiply each of the prime numbers with each having its highest power

\;\text{ L.C.M }\;=3^{2} \times 7=9 \times 7=63

Now express each fraction to have 63 as the denominator

Since the denominators are the same, you can compare them by the numerators

The question said in ascending order, hence lowest to highest

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