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BECE Mathematics 2018 Paper

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Question : 20

Total: 40

Find the slope of the line

3x-6y=33

-3
$-\frac{1}{2}$
$\frac{1}{2}$
3

Solution:

Concept:

The slope of a line is the coefficient of

x

when the equation is written in the form

y = mx + c

.

Explanation:

Start with the given equation:

3x - 6y = 33

Subtract

3x

from both sides:

-6y = -3x + 33

Divide every term by

-6

to isolate

y

:

y = \frac{-3x + 33}{-6}

Simplify the fraction:

y = \frac{1}{2}x - \frac{11}{2}

Now compare with

y = mx + c

.

The slope

m

is

\frac{1}{2}

.

Answer:

C.

\frac{1}{2}

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