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BECE Mathematics 2018 Paper

Question : 21

Total: 40

y=c+b x^{2}

y

c=\frac{14}{5}, b=\frac{4}{5}

x=2

Solution:

Concept:

Substitute the given values into the algebraic expression and simplify.

Explanation:

We are given

y = c + b x^{2}

The values are

c = \frac{14}{5}

b = \frac{4}{5}

, and

x = 2

Substitute these values into the expression.

y = \frac{14}{5} + \frac{4}{5} \times (2)^{2}

First, calculate the square:

2^{2} = 4

So,

y = \frac{14}{5} + \frac{4}{5} \times 4

Multiply the fraction:

\frac{4}{5} \times 4 = \frac{16}{5}

Add the fractions because they have the same denominator.

y = \frac{14}{5} + \frac{16}{5} = \frac{14+16}{5}

y = \frac{30}{5} = 6

Hence, the correct option is C.

Answer:

y = 6

(Option C).

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