BECE Mathematics 2020 Paper

Concept:If a point $(x, y)$ is translated by a vector $\begin{pmatrix} -2 \\ 3 \end{pmatrix}$, its image is $(x-2,\ y+3)$.Solution:The image is given as $P'(4,-5)$ and the translation vector is $r=\begin{pmatrix} -2 \\ 3 \end{pmatrix}$.For the $x$-coordinate: $4 = x + (-2) = x - 2$.So, $x = 4 + 2 = 6$.For the $y$-coordinate: $-5 = y + 3$.So, $y = -5 - 3 = -8$.Hence, the original point is $(6,-8)$.Answer:Option C ($(6, -8)$)