BECE Mathematics 2020 Paper

Concept:Substitute the given value of $x$ into the equation and solve for $y$.Solution:Given: $2y = 1 - 3x^2 + 4x$When $x = -1$, replace every $x$ with $-1$$2y = 1 - 3(-1)^2 + 4(-1)$Compute $(-1)^2 = 1$, so $-3(1) = -3$Also $4(-1) = -4$Thus $2y = 1 - 3 - 4$$2y = 1 - 7 = -6$Divide both sides by 2$y = \frac{-6}{2} = -3$Answer:Option A ($-3$)