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BECE Mathematics 2020 Paper
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© africaexams.com
Question : 35
Total: 40
Solve:
3
−
(
3
x
+
4
)
≤
−
4
x
≤
1
x
≥
1
x
≥
12
∕
3
x
<
11
∕
2
Validate
Solution:
3
−
(
3
x
+
4
)
≤
−
4
Concept
a
(
b
+
c
)
=
a
x
b
+
a
x
c
−
a
(
b
+
c
)
=
−
a
×
b
+
−
a
x
c
−
(
a
+
b
)
=
−
1
(
a
+
b
)
=
−
1
×
a
+
−
1
×
b
⇒
−
(
3
x
+
4
)
=
−
1
(
3
x
+
4
)
=
−
1
×
3
x
+
−
1
×
4
=
−
3
x
−
4
3
−
(
3
x
+
4
)
≤
−
4
⇒
3
−
3
x
−
4
≤
−
4
⇒
3
−
4
−
3
x
≤
−
4
⇒
−
1
−
3
x
≤
−
4
Moving the
−
3
x
to the right side of the equation and the -4 to the left
⇒
−
1
+
4
≤
3
x
3
≤
3
x
Divide both sides by 3
3
∕
3
≤
3
x
∕
3
⇒
1
≤
x
You can reverse the order and reverse the inequality sign
⇒
x
≥
1
© africaexams.com
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