3−(3x+4)≤−4Concepta(b+c)=a×b+a×c−a(b+c)=−a×b+−a×c−(a+b)=−1(a+b)=−1×a+−1×b⇒−(3x+4)=−1(3x+4)=−1×3x+−1×4=−3x−43−(3x+4)≤−4⇒3−3x−4≤−4⇒3−4−3x≤−4⇒−1−3x≤−4 Moving the −3x to the right side of the equation and the -4 to the left⇒−1+4≤3x3≤3xDivide both sides by 333≤33x⇒1≤xYou can reverse the order and reverse the inequality sign⇒x≥1