BECE Mathematics 2021 Paper

You can make time the subject of the equationSince time is dividing, you can multiply both sides of the equation by time to cancel the time at the right hand sideTime $\times$ Speed $=$ DistanceDivide both sides by SpeedFrom the question, distance covered $=150\,\text{km}$Speed was $18\,\text{km}/\text{h}$ $\text{ Time } =\frac{150}{18}$3 goes into 150, 50 times and 18, 6 times$\text{ Time } =\frac{50}{6}$2 goes into 50, 25 times and 6, 3 times$\text{ Time } =\frac{25}{3}$ 3 can go into 25,8 times remainder 1Time $=\frac{81}{3}$ hours, thus 8 whole number 1 over 3You can change the fraction part of the hours to minutes by multiplying by 60 minutes. There are 60 minutes in an hour$\frac{1}{3}\ \text{ hours }=\frac{1}{3}\times 60\ \text{ minutes }=20\ \text{ minutes }$Therefore the time taken is 8 hours 20 minutes