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BECE Mathematics 2022 Paper

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Question : 11

Total: 40

Given that

P(3,-2)

Q(-2,4)

are points in a plane, find the gradient of the line joining

P

Q

$-\frac{6}{5}$
$\frac{6}{5}$
$\frac{5}{6}$
$\;\; -\frac{5}{6}$

Solution:

Gradient of a line

=

change in

y /

change in

x = \frac{(y_2 - y_1)}{(x_2 - x_1)}

The general point of a line is in the form

(x, y)

, thus the first cordinate is

x

and the second cordinate is

y

P(3,-2)

and

Q(-2,4)

y_2 = 4

and

y_1 = -2

x_2 = -2

and

x_1 = 3

Gradient

= \frac{(4-2)}{(-2-3)}

-- = +

Gradient

= \frac{(4+2)}{(-2-3)} = \frac{6}{-5} = -\frac{6}{5}

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