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JAMB Chemistry 2018 Paper

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Question : 45

Total: 87

In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid?

5cm $^3$
10cm $^3$
20cm $^3$
50cm $^3$

Solution:

2NaOH + H $_2$ SO $_4$ ↔Na $_2$ SO $_4$ + 2H $_2$ O

V x 0.5M = 2(10 x 1.25)

0.5V = 2 x 12.5

0.5V = 25

V = 250.5 = 50cm $^2$

Correct computation as it follows the equation specified.

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