JAMB Chemistry 2018 Paper

From the dilution law

C$_{1}$V$_{1}$ = C$_{2}$V$_{2}$

C$_{1}$ = Initial Concentration of NaOH = 0.6M

V$_{1}$ = Initial Volume of NaOH = 300cm3

C$_{2}$ = Final Concentration of NaOH = 0.4M

V$_{2}$ = Final Volume of NaOH = ?

V$_{2}$ = $\frac{C_1V_1}{C_2}$

V$_{2}$ = $\frac{0.6 \times 300}{0.4}$

V$_{2}$ = 450 cm$^{3}$

Correct Computation as it follows the equation specified