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JAMB Mathematics 2019 Paper

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Question : 29

Total: 73

The nth term of a sequence is given by 2

^{2n - 1}

. Find the sum of the first four terms.

74
32
42
170

Solution:

$T_n = 2^{2n - 1}$

$T_1 = 2^{2(1) - 1}$

= 2

$T_2 = 2^{2(2) - 1}$

= 8

$T_3 = 2^{2(3) - 1}$

= 32

$T_4 = 2^{2(4) - 1}$

= 128

$T_1 + T_2 + T_3 + T_4 = 2 + 8 + 32 + 128$

= 170

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