2∫−1(2x2+x)dx
= [2x2+13+x1+12]−12
= [2x33+x22]−12
= (2(2)33+222)−(2(−1)33+(−1)22)
= (163+2)−(−23+12)
= 223−(−16)
= 223+16
= 152
= 712