tanθ=920=0.45\tan \theta = \frac{9}{20} = 0.45tanθ=209=0.45
θ=tan−1(0.45)\theta = \tan^{-1}(0.45)θ=tan−1(0.45)
= 24.23°
∴\therefore∴ The bearing of Y from X = 180° - 24.23°
= 155.77°
= 156° (to the nearest degree)
