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JAMB Mathematics 2019 Paper

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Question : 44

Total: 73

If

P = \left(\frac{Q(R - T)}{15}\right)^{\frac{1}{3}}

, make T the subject of the formula.

$T = \frac{15R - Q}{P^3}$
$T = R - \frac{15P^3}{Q}$
$T = \frac{R - 15P^3}{Q}$
$T = \frac{R + P^3}{15Q}$

Solution:

$P = \left(\frac{Q(R - T)}{15}\right)^{\frac{1}{3}}$

$P^3 = \frac{Q(R - T)}{15}$

$Q(R - T) = 15P^3$

$R - T = \frac{15P^3}{Q}$

$T = R - \frac{15P^3}{Q}$

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