Given that sec2^22θ + tan2^22θ = 3
Where sec2^22θ = 1 + tan2^22θ
: 1 + tan2^22θ + tan2^22θ = 3
2tan2^22θ = 3 - 1
2tan2^22θ = 2
divide both sides by 2
tan2^22θ = 1
tanθ = √1
tanθ = 1
θ = tan−1^{-1}−1 (1)
θ = 45º
