x3+6x−7x−1\frac{x^3 + 6x - 7}{x-1}x−1x3+6x−7:
When numerator is differentiated → 3x2^{2}2 + 6
When denominator is differentiated → 1
: 3x2+61\frac{3x^2 + 6}{1}13x2+6
substitute x for 1
3⋅12+61\frac{3 \cdot 1^2 + 6}{1}13⋅12+6 = 3+61\frac{3 + 6}{1}13+6
= 91\frac{9}{1}19
= 9
