Differentiate the function y = [3]{x²(2x - x²)

Correct Answer is : dydx=10x2/33−8x5/33dy/dx = {10x²/3}}{3} - {8x^{5/3}}{3}dxdy=310x2/3−38x5/3

dy/dx = {10x^{5/3}}{3} - {8x²/3}}{3}

dy/dx = {10x²/3}}{3} - {8x^{5/3}}{3}

dy/dx = {10x^{5/3}}{3} - {8x^{5/3}}{3}

dy/dx = {10x²/3}}{3} - {8x²/3}}{3}

Correct Answer is : dydx=10x2/33−8x5/33dy/dx = {10x²/3}}{3} - {8x^{5/3}}{3}dxdy=310x2/3−38x5/3

Test Index

JAMB Mathematics 2023 Paper

Question : 23

Total: 80

\sqrt[3]{x^2}(2x - x^2)

Solution:

y = $\sqrt[3]{x^2(2x - x^2)} = x^{2/3} (2x - x^2)$

= $2x^{5/3} - x^{8/3}$

Now, we can differentiate the function

$\therefore \frac{dy}{dx} = \frac{10x^{2/3}}{3} - \frac{8x^{5/3}}{3}$

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