Test Index

JAMB Physics 2018 Paper

Question : 84

Total: 87

Solution:

Concept:

Electrical energy dissipated by a resistor is the product of the power drawn and the time for which it operates.

Explanation:

The power drawn by the resistor is calculated using:

P = IV = (2\,\text{A})(12\,\text{V}) = 24\,\text{W}

This means the resistor dissipates

24

joules of energy per second.

The total time in seconds is:

t = 5 \times 60 = 300\,\text{s}

Energy dissipated is:

E = Pt = (24)(300) = 7{,}200\,\text{J}

Answer:

7{,}200\,\text{J}

(Option C).

Go to Question:

Prev Question

Next Question