Energy of the emitted photon(E) = hc λ\frac{\;\text{hc}\;}{\lambda}λhc
λ\lambdaλ = 5.68 x 10−6^{-6}−6m
h = 6.63 x 10−34^{-34}−34Js
c = 3.0 x 108^88ms−1^{-1}−1
E = (6.63×10−34)×(3.0×108)5.68×10−6\frac{\;(6.63 \times 10^{-34}) \times (3.0 \times 10^8)}{5.68 \times 10^{-6}}5.68×10−6(6.63×10−34)×(3.0×108) = 1.989×10−255.68×10−6\frac{\;1.989 \times 10^{-25}}{5.68 \times 10^{-6}}5.68×10−61.989×10−25
E = 3.50 x 10−20^{-20}−20J
Therefore, the energy change = 3.50 x 10−20^{-20}−20J
