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JAMB Physics 2024 Paper

Question : 62

Total: 125

Using the diagram above, the effective force pushing it forward at an angle 60º is

Solution:

The effective force pushing it forward is the horizontal component of the force = F $\_x$ = F Cos $\theta$

F $\_x$ = F Cos $\theta$ = 50 x Cos 60º = 50 x 0.5 = 25N

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