C3H8 + 5 O2 → 3CO2 + 4H2O
From the equation: 1 mole : 3 moles
If 0.1 mole reacted, then 0.3 mole will be formed.
⇒ 0.3 mole of CO2 will be produced.
Recall that Number of moles of gases = VolumeMolarVolumeofgasatstp
n = VM.V
0.3 = V22.4
V = 0.3 x 22.4
V = 6.72 dm3