WAEC Chemistry 2024 Paper

C$_{3}$H$_{8}$ + 5 O$_{2}$ → 3CO$_{2}$ + 4H$_{2}$O

From the equation: 1 mole : 3 moles

If 0.1 mole reacted, then 0.3 mole will be formed.

⇒ 0.3 mole of CO$_{2}$ will be produced.

Recall that Number of moles of gases = $\frac{\text{Volume}}{\text{Molar Volume of gas at stp}}$

n = $\frac{V}{\text{M.V}}$

0.3 = $\frac{V}{22.4}$

V = 0.3 x 22.4

V = 6.72 dm$^{3}$