Using remainder theorem, the remainder when 5x3+2x2−7x−55x^{3} + 2x^{2} - 7x -55x3+2x2−7x−5 is divided by (x - 2) = f(2)
f(2)=5(23)+2(22)−7(2)−5=40+8−14−5f(2) = 5(2^{3}) + 2(2^{2}) - 7(2) -5 = 40 + 8 - 14 - 5f(2)=5(23)+2(22)−7(2)−5=40+8−14−5
= 29
