f(x)=3x+1x2−1f(x) = \frac{3x+1}{x^{2}-1}f(x)=x2−13x+1
f(−3)=3(−3)+1(−3)2−1=−88=−1f(-3) = \frac{3(-3)+1}{(-3)^{2}-1} = \frac{-8}{8} = -1f(−3)=(−3)2−13(−3)+1=8−8=−1
